0

Application For Bernoulli's Equation



The Bernoulli equation can be applied to a great many 
situations not just the pipe flow we have been considering 
up to now. In the following sections we will see some 
examples of its application to flow measurement from tanks,
within pipes as well as in open channels.


Flow from a Tank through a small Orifice


Liquid flows from a tank through a orifice close to 
the bottom. The Bernoulli equation can be adapted to a streamline from the surface (1) to the orifice (2) as (e1):





Since (1) and (2)'s heights from a common reference is related as (e2), and the equation of continuity can be expressed as (e3), it's possible to transform (e1) to (e4).


Pitot Tube


If a stream of uniform velocity flows into a blunt body, the stream lines take a pattern similar to this:








Note how some move to the left and some to the right. But one, in the centre, goes to the tip of the blunt body and stops. It stops because at this point the velocity is zero - the fluid does not move at this one point. This point is known as the stagnation point.

From the Bernoulli equation we can calculate the pressure at this point. Apply Bernoulli along the central streamline from a point upstream where the velocity is u1 and the pressure p1 to the stagnation point of the blunt body where the velocity is zero, u2 = 0. Also z1 = z2.




This increase in pressure which bring the fluid to rest is 

called the dynamic pressure.



Dynamic pressure = 
or converting this to head (using )



Dynamic head = 



The total pressure is know as the stagnation 

pressure (or total pressure)


Stagnation pressure = 



or in terms of head
Stagnation head = 



The blunt body stopping the fluid does not have to be a solid. 

I could be a static column of fluid. Two piezometers, one as 

normal and one as a Pitot tube within the pipe can be used 

in an arrangement shown below to measure velocity of flow.





Using the above theory, we have the equation for p2 ,





We now have an expression for velocity obtained from two 

pressure measurements and the application of the Bernoulli 

equation.



Example


The outlet velocity of a pressurized tank where
p1 = 0.2 (MN/m2)
p2 = 0.1 (MN/m2)
A2 / A1 = 0.01
h = 10 (m)
can be calculated as
V2 = ( (2 / (1 - (0.01)2) ((0.2 106 N/m2) - (0.1 106 N/m2)) / (1000 kg/m3) + (9.81 m/s2) (10 m)))1/2
        = 19.9 (m/s)


0 comments:

Post a Comment