Bernoulli's Equation
Definition :
- The Bernoulli Equation can be considered to be a statement of the conservation of energy principle appropriate for flowing fluids.
- The qualitative behavior that is usually labeled with the term "Bernoulli effect" is the lowering of fluid pressure in regions where the flow velocity is increased.
- This lowering of pressure in a constriction of a flow path may seem counterintuitive, but seems less so when you consider pressure to be energy density.
In the high velocity flow through
the constriction, kinetic energy must increase at the expense of pressure
energy.
where,
·
points 1 and 2 lie on a streamline,
·
the fluid has constant density,
·
the flow is steady, and
·
there is no friction.
Although these
restrictions sound severe, the Bernoulli
equation is very useful, partly
because it is very simple to use
and partly because it can give great insight
into the balance between pressure, velocity and elevation.
Examples
Water circulates throughout a house in a
hot-water heating system. If water is pumped out at a speed of 0.50 m/s through
a 4.0 cm diameter pipe in the basement under a pressure of 3.0 atm, what will
be the flow speed and pressure in a 2.6 cm diameter pipe on the second floor
5.0 m above? Assume pipes do not divide into branches.
Solution:
First
calculate the flow speed on the second floor, calling it v2, using
the equation of continuity. We can call the basement point 1.
v2 =
(v1A1) / (A2) = (v1π(r1)2)
/ (π(r2)2) = (0.50 m/s)(0.020 m)2 /
(0.013 m)2 =
1.2 m/s
To find
pressure, we use Bernoulli’s equation:
P2 = P1 +
ρg(h1– h2) + ½ρ((v1)2 –
(v2)2)
P2 = (3.0 x 105 N/m2) + (1.0 x 103 kg/m3) [ (0.50 m/s)2 – (1.2 m/s)2]
P2 = (3.0 x 105 N/m2) – (4.9 x 104 N/m2) – (6.0 x 102 N/m2)
P2 = (3.0 x 105 N/m2) + (1.0 x 103 kg/m3) [ (0.50 m/s)2 – (1.2 m/s)2]
P2 = (3.0 x 105 N/m2) – (4.9 x 104 N/m2) – (6.0 x 102 N/m2)
P2 = 2.5
x 105N/m2
What is the
lift (in newtons) due to Bernoulli’s principle on a wing of area 86 m2 if the
air passes over the top and bottom surfaces at speeds of 340 m/s and 290 m/s,
respectively?
Solution:
P1 +
½ρ(v1)2 = P2 +
½ρ(v2)2
P1- P2 = (0.5)(1.29)(340)2 – (0.5)(1.29)(290)2
P1- P2 = 20317.5
P1- P2 = (0.5)(1.29)(340)2 – (0.5)(1.29)(290)2
P1- P2 = 20317.5
F = PA =
(20317.5)(86)
F= 1747305N
F= 1747305N
F = 1.7 x 106
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thanks
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